7 Use constants of motion to determine orbit loss

This section discusses determining the prompt loss of ions by using the constants of motion. This work was motivated by Dr. Chengkang Pan, who shares an office with me and recently (2014) published a NF paper discussing this topic.

7.1 Critical velocity for ions to touch a boundary

There are three constants of motion for a guiding center drift, namely, the canonical toroidal angular momentum Pϕ, the magnetic moment μ, and the total kinetic energy 𝜀, which are given, respectively, by

       g(Ψ-)
Pϕ = m  B  vξ + ZeΨ,
(116)

μ = m-v2(1− ξ2),
    B
(117)

𝜀 = 1mv2,
    2
(118)

where g(Ψ) = RBϕ, ξ is the cosine of the pitch angle of guiding center velocity (with respect to the local magnetic field), Ψ = RAϕ with Aϕ being the toroidal component of the magnetic vector potential, Ze and m are the charge and mass of the ion, respectively.

Next, we use the constraint of the three constants of motion to determine whether an ion with a given initial condition can reach a boundary magnetic surface labeled by Ψa. The initial conditions of an ion is denoted with 0,B0,v00), where Ψ0 labels the flux surface where the particle is initially located, B0 is the magnetic field strength at the initial location of the guiding-center, v0 and ξ0 are the initial velocity and pitch angle. The conditions of the particle when it reach the boundary flux surface are denoted with a,Ba,vaa). Then the conservation of Pϕ requires

m g(Ψ0)v ξ + eΨ = m g(Ψa-)v ξ + eΨ  .
   B0   0 0    0      Ba  a a     a
(119)

Using the conservation of the kinetic energy, the above equation is written

    (g(Ψ )     g(Ψ  ) )
mv0  ----0ξ0 − ---a-ξa  = e(Ψa − Ψ0).
       B0       Ba
(120)

Using the conservation of μ, we obtain

    2       2
1−-ξa-= 1−-ξ0,
 Ba      B0
(121)

which can be written

      ∘ -------------
ξa = ±  1− Ba-(1− ξ20).
           B0
(122)

where we does not distinguish between circulating particles and trapped particles. If a particle is a circulating one, then v does not change sign and thus ξ does not change sign either. In this case, equation (122) is written

          ∘ -------------
ξa = sign(ξ0) 1 − Ba(1 − ξ20).
                B0
(123)

If a particle is a trapped one, then both signs ± in Eq. (122) are possible.

Using Eq. (122), equation (120) is written

    [              ∘ -------------]
mv   g(Ψ0)ξ ∓ g(Ψa)  1 − Ba(1− ξ2) = e(Ψ  − Ψ ),
  0   B0   0   Ba        B0     0        a   0
(124)

which can be arranged in the form

    e(Ψ  − Ψ )( g(Ψ )    g(Ψ )∘ ----B--------) −1
v0 =---a----0-  ---0-ξ0 ∓----a  1 − -a(1 − ξ20)   ,
        m        B0        Ba       B0
(125)

Equation (125) gives the velocity v0 needed for the particle to reach the flux surface Ψa. The value of v0 given by Eq. (125) varies, depending on the value of Ba, i.e., depending on the poloidal location on the boundary magnetic flux surface. By scanning the poloidal location on the boundary flux surface, we can obtain the minimum value of v0, v0 min, which is the minimum velocity for a particle with the initial condition 0,B00) to reach the flux surface Ψa.

To evaluate the minimum energy for the ions to be lost, we need choose a specific magnetic configuration. Next, we consider a simple large aspect ratio magnetic configuration.

7.2 Large aspect ratio equilibrium

Define (r,𝜃,ϕ) coordinates by

R(r,𝜃) = Raxis + rcos𝜃,
(126)

Z(r,𝜃) = rsin 𝜃,
(127)

where (R,ϕ,Z) are the cylindrical coordinates and Raxis is a constant. The Jacobian 𝒥 of (r,𝜃,ϕ) coordinates can be calculated using the definition, yielding 𝒥 = Rr (refer to my notes on equilibrium).

In (r,𝜃) coordinates, the toroidal elliptic operator ΔΨ is given by (refer to my notes on equilibrium):

                    2               (                  )
Δ ⋆Ψ = 1-∂r ∂Ψ-+ 12 ∂-Ψ2 −----1----  ∂Ψ-cos𝜃 − ∂Ψ-1sin𝜃  .
       r∂r  ∂r   r ∂ 𝜃   R0 + rcos𝜃   ∂r       ∂𝜃 r
(128)

Assume that the toroidal current density Jϕ is given and is uniform distributed, Jϕ = I∕S, where I is the total current within a boundary magnetic surface, S is the poloidal area enclosed by the boundary magnetic surface Since Jϕ is given, then the expression Jϕ =  1
μ0RΔΨ can be used as a constraint for Ψ, i.e.,

1 ∂  ∂Ψ    1 ∂2Ψ        1      ( ∂Ψ       ∂Ψ 1    )                    I
- --r---+  2---2-− ------------  ---cos𝜃− ---- sin𝜃  = − μ0(Raxis + rcos𝜃)-,
r ∂r ∂r    r ∂𝜃    Raxis +r cos𝜃  ∂r        ∂𝜃r                         S
(129)

We consider the region 𝜀 = r∕Raxis 1 (large aspect ratio regime), and further assume the following orderings

    ∂Ψ
Raxis∂r- ∼ O(𝜀−1)Ψ,
(130)

and

∂Ψ-∼ O (𝜀0)Ψ.
∂𝜃
(131)

Then the leading order of Eq. (129) is written as

1-∂r ∂Ψ-= − μ R   I.
r∂r  ∂r      0 axisS
(132)

One solution to the above equation is

Ψ = − μ0IRaxisr2.
      4S
(133)

In the (r,𝜃,ϕ) coordinates, the gradient of Ψ is written

        ∂Ψ      ∂Ψ      ∂Ψ
∇Ψ   =  -∂r ∇r + ∂𝜃-∇ 𝜃+ ∂ϕ-∇ϕ
          μ I
     =  − -0-Raxisr∇r                              (134)
          2S
Then the poloidal magnetic field is written as
Bp  =  ∇ Ψ × ∇ϕ
         μ I
    =  − -0-Raxisr∇r × ∇ ϕ
          2S       (      )
    =  − μ0IRaxisr − 1-∂r- .                     (135)
          2S          𝒥 ∂𝜃
In terms of the cylindrical coordinate system (R,ϕ,Z) and its unit basis vector eR and eZ , a location vector r is written as
r = R(r,𝜃)eR (ϕ) + Z(r,𝜃)eZ,
(136)

then in (r,𝜃,ϕ) coordinates, we obtain

∂r ||       ∂R        ∂Z
∂𝜃-||   =   ∂𝜃-eR(ϕ)+ ∂𝜃-eZ
   r,ϕ
       =   − rsin𝜃eR(ϕ)+ rcos𝜃eZ
       =   − rˆe𝜃,                                  (137)
where  ˆe𝜃 = cos𝜃eZ sin𝜃eR(ϕ) is a unit vector. Then Eq. (135) is written as
                  (      )
Bp   =  − μ0IRaxisr  −-reˆ𝜃
          2S         Rr
          μ0I------r-----
     =  − 2S 1 + Rraxis cos𝜃ˆe𝜃                     (138)
The toroidal component of the magnetic field is written
      g(Ψ-)   ---g(Ψ-)----
B ϕ =  R  =  Raxis + rcos𝜃.
(139)

Consider the case that g(Ψ) is a constant function, g(Ψ) = Bϕ0Raxis, then Eq. (139) is written

          B
B ϕ =-----rϕ0----
     1 + Raxis cos𝜃
(140)

I am curious about what the safety factor q looks like for the above flat current density profile. Let us calculate q by using q = dΨt∕dΨp.

      ∮              ∮  r
dΨt =   drBϕdℓp = drg  R-d𝜃
(141)

      μ0I
dΨp = 4S-Raxis2rdr
(142)

Then

             ∮ g-         ∮-1             ∮
q = dΨt-= μdrI--Rrd𝜃--=  gμI-R-d𝜃-=  μI-g----  ---1----d𝜃.
   dΨp    40S-Raxis2rdr   40S Raxis2  20S R2axis  1+ 𝜀cos𝜃
(143)

Using maxima to perform the above integral, the above expression is written as

q =-μ0Ig-2--√-2π---=  -4πSg2--√--1---.
    2S R axis 1− 𝜀2   μ0IRaxis  1− 𝜀2
(144)

 

 


pict

Figure 28: Minimum loss energy as a function of the cosine of the launching pitch angle. ρ = 0.98

 

 

———————————

The minimum value of v0, denoted with v0 min, is reached when 𝜃 = π or 𝜃 = 0 depends on the ± in Eq. (??).

 

 

 

 

 

 

                      (            --   ∘ ---------------)− 1
v0 =--e- μ0I-R-(a2 − r2)( ξ0 ∓ sign(ξ0)R-+-a 1− R-+-r(1− ξ20))   .
    mR0  4πa2                      R + r     R + a
(145)

 

v0min(ξ0) = max(min(v0(ξ0,𝜃)),0)
(146)

 

 

 

 

(in practice ψa is usually different from the actual poloidal flux Ψp and is related to Ψp by ψa = ±|Ψp|2π + C, where C is a constant)

 

We consider the confinement of the particles. The method is to determine whether the particles can reach a boundary flux surface by making use of the three constants of the motion. The boundary flux surface is labeled by ψa, where ψa is the poloidal flux within that flux surface.