Toroidal force balance

Next, consider the $ \phi $ component of Eq. (43), which is written

$\displaystyle J_Z B_R - J_R B_Z = \frac{1}{R} \frac{\partial P}{\partial \phi} .$ (45)

Since $ P = P (\Psi)$, which implies $ \partial P / \partial \phi = 0$, equation (45) reduces to

$\displaystyle J_Z B_R - J_R B_Z = 0$ (46)

Using the expressions of the poloidal current density (37) and (38) in the force balance equation (46) yields

$\displaystyle \frac{\partial g}{\partial R} B_R + \frac{\partial g}{\partial Z} B_Z = 0,$ (47)

which can be further written

$\displaystyle \mathbf{B} \cdot \nabla g = 0.$ (48)

According to the same reasoning for the pressure, we conclude that Eq. (48) is equivalent to $ g = g (\Psi)$. (The function $ g$ defined here is usually called the ``poloidal current function'' in tokamak literature. The reason for this name is discussed in Sec. 2.3.)

yj 2018-03-09