Contours of $ \Psi $ on $ (R, Z)$ plane are magnetic surfaces

Because $ \Psi $ is constant along a magnetic field line and $ \Psi $ is independent of $ \phi $, it follows that the projection of a magnetic field line onto $ (R, Z)$ plane is a contour of $ \Psi $. On the other hand, it is ready to prove that the contour of $ \Psi $ on $ (R, Z)$ plane is also the projection of a magnetic field line onto the plane, i.e., a magnetic surface. [Proof. The contour of $ \Psi $ on $ (R, Z)$ plane is written

$\displaystyle d \Psi = 0,$ (13)

i.e.,

$\displaystyle \frac{\partial \Psi}{\partial R} d R + \frac{\partial \Psi}{\partial Z} d Z = 0.$ (14)

$\displaystyle \Rightarrow \frac{1}{R} \frac{\partial \Psi}{\partial R} d R + \frac{1}{R} \frac{\partial \Psi}{\partial Z} d Z = 0.$ (15)

Using Eqs. (4) and (5), the above equation is written

$\displaystyle B_Z d R - B_R d Z = 0,$ (16)

i.e.,

$\displaystyle \frac{d Z}{d R} = \frac{B_Z}{B_R},$ (17)

which is the equation of the projection of a magnetic field line on $ (R, Z)$ plane. Thus, we prove that the contour of $ \Psi $ is also the projection of a magnetic field line on $ (R, Z)$ plane.]

yj 2018-03-09