Relation between the partial derivatives in $ (\psi , \theta , \phi )$ and $ (\psi , \theta , \zeta )$ coordinates

Noting the simple fact that

$\displaystyle \frac{d}{d x} = \frac{d}{d (x + c)},$ (251)

where $ c$ is a constant, we conclude that

$\displaystyle \left( \frac{\partial f}{\partial \zeta} \right)_{\psi, \theta} = \left( \frac{\partial f}{\partial \phi} \right)_{\psi, \theta},$ (252)

(since $ \phi = \zeta + q (\psi) \delta (\psi, \theta)$, where the part $ q
(\psi) \delta (\psi, \theta)$ acts as a constant when we hold $ \psi $ and $ \theta $ constant), i.e., the symmetry property with respect to the new toroidal angle $ \zeta $ is identical with the one with respect to the old toroidal angle $ \phi $. On the other hand, generally we have

$\displaystyle \left( \frac{\partial f}{\partial \psi} \right)_{\theta, \zeta} \neq \left( \frac{\partial f}{\partial \psi} \right)_{\theta, \phi}$ (253)

and

$\displaystyle \left( \frac{\partial f}{\partial \theta} \right)_{\psi, \zeta} \neq \left( \frac{\partial f}{\partial \theta} \right)_{\psi, \phi} .$ (254)

In the special case that $ f$ is axisymmetric (i.e., $ f$ is independent of $ \phi $ in $ (\psi , \theta , \phi )$ coordinates), then two sides of Eqs. (253) and (254) are equal to each other. Note that the partial derivatives $ \partial / \partial \psi$ and $ \partial / \partial
\theta$ in Sec. 7.1 and 7.2 are taken in $ (\psi , \theta , \phi )$ coordinates. Because the quantities involved in Sec. 7.1 and 7.2 are axisymmetric, these partial derivatives are equal to their counterparts in $ (\psi , \theta , \zeta )$ coordinates.

yj 2018-03-09